# FizzBuzz

A Roc solution to the popular FizzBuzz interview problem:

Print the integers from 1 to 100, replacing multiples of three with "Fizz", multiples of five with "Buzz", and multiples of both three and five with "FizzBuzz".

## Code

```app [main] { pf: platform "https://github.com/roc-lang/basic-cli/releases/download/0.15.0/SlwdbJ-3GR7uBWQo6zlmYWNYOxnvo8r6YABXD-45UOw.tar.br" }

import pf.Stdout

main =
List.range { start: At 1, end: At 100 }
|> List.map fizzBuzz
|> Str.joinWith ","
|> Stdout.line

## Determine the FizzBuzz value for a given integer.
## Returns "Fizz" for multiples of 3, "Buzz" for
## multiples of 5, "FizzBuzz" for multiples of both
## 3 and 5, and the original number for anything else.
fizzBuzz : I32 -> Str
fizzBuzz = \n ->
fizz = n % 3 == 0
buzz = n % 5 == 0

if fizz && buzz then
"FizzBuzz"
else if fizz then
"Fizz"
else if buzz then
"Buzz"
else
Num.toStr n

## Test Case 1: not a multiple of 3 or 5
expect fizzBuzz 1 == "1"
expect fizzBuzz 7 == "7"

## Test Case 2: multiple of 3
expect fizzBuzz 3 == "Fizz"
expect fizzBuzz 9 == "Fizz"

## Test Case 3: multiple of 5
expect fizzBuzz 5 == "Buzz"
expect fizzBuzz 20 == "Buzz"

## Test Case 4: multiple of both 3 and 5
expect fizzBuzz 15 == "FizzBuzz"
expect fizzBuzz 45 == "FizzBuzz"```

## Output

Run this from the directory that has `main.roc` in it:

```\$ roc main.roc
1,2,Fizz,4,Buzz,Fizz,7,8,Fizz,Buzz,11,Fizz,13,14,FizzBuzz,16,17,Fizz,19,Buzz,Fizz,22,23,Fizz,Buzz,26,Fizz,28,29,FizzBuzz,31,32,Fizz,34,Buzz,Fizz,37,38,Fizz,Buzz,41,Fizz,43,44,FizzBuzz,46,47,Fizz,49,Buzz,Fizz,52,53,Fizz,Buzz,56,Fizz,58,59,FizzBuzz,61,62,Fizz,64,Buzz,Fizz,67,68,Fizz,Buzz,71,Fizz,73,74,FizzBuzz,76,77,Fizz,79,Buzz,Fizz,82,83,Fizz,Buzz,86,Fizz,88,89,FizzBuzz,91,92,Fizz,94,Buzz,Fizz,97,98,Fizz,Buzz
```

You can also use `roc test` to run the tests.